請問一下log計算過程

log0.96^n=log0.3怎麼轉換成n(5log2 log3-2)=log3-1
log0.96^n=log0.3n*log(96/100)=log(3/10)n*[log(2^5*3)-log100]=log3-log10n*[(log2^5) (log3)-2]=(log3)-1n*[(5*log2) (log3)-2]=(log3)-1My blog:http://tw.myblog.yahoo.com/math-life
log0.96^n=n(log0.96)=n(log96/100)=n(log96-2)=n(log32*3-2)=n(log2^5 log3-2)=n(5log2 log3-2)log0.3=log3/10=log3-1所以n(5log2 log3-2)=log3-1
n(5*0.3010 0.4771-2)=0.4771-1n*(-0.0179)=-0.5229n=29.2122905------

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